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Hello:
I have a query where I’m trying to insert data using the ON DUPLICATE KEY syntax.
When I run the script, I receive the following message:
FS30YF100FS30YF100Unknown column ‘a’ in ‘field list’.
Can someone help me with this error message?
Thank you in advance. If you need any other info, I’ll be happy to pass it along. I just don’t know what info you may need so I’m showing the script that produces the error message.
This is the code:
[code=php]
<?php
//session_start();
include(‘header.html’);
require_once (‘mysql_connect.php’);
$query = “SELECT a.id, a.lender_code, b.id, b.program_code, CONCAT(a.lender_code,b.program_code) AS prl FROM lender a, loan_program b
WHERE a.id=$_SESSION[lender_id] AND b.id=$_SESSION[program_id]”;
$result = @mysql_query ($query) or die (mysql_error());
if ($result) {
while($row=@mysql_fetch_array($result, MYSQL_ASSOC))
{
$lender_code = $row[‘lender_code’];
$program_code = $row[‘program_code’];
$prl = $row[‘prl’];
echo $lender_code;
echo $program_code;
echo $prl;
}
}
$query2 = “INSERT INTO test (program_id, program_code, lender_id, lender_code, prog_lend, rate, price, date, time)
VALUES (‘$_SESSION[program_id]’,’$_SESSION[program_code]’,’$_SESSION[lender_id]’,’$_SESSION[lender_code]’,’$prl’,’$_SESSION[rate1]’,’$_SESSION[price1]’, CURRENT_DATE, CURRENT_TIME),
(‘$_SESSION[program_id]’,’$_SESSION[program_code]’,’$_SESSION[lender_id]’,’$_SESSION[lender_code]’,’$prl’,’$_SESSION[rate2]’,’$_SESSION[price2]’, CURRENT_DATE, CURRENT_TIME),
(‘$_SESSION[program_id]’,’$_SESSION[program_code]’,’$_SESSION[lender_id]’,’$_SESSION[lender_code]’,’$prl’,’$_SESSION[rate3]’,’$_SESSION[price3]’, CURRENT_DATE, CURRENT_TIME),
(‘$_SESSION[program_id]’,’$_SESSION[program_code]’,’$_SESSION[lender_id]’,’$_SESSION[lender_code]’,’$prl’,’$_SESSION[rate4]’,’$_SESSION[price4]’, CURRENT_DATE, CURRENT_TIME)
ON DUPLICATE KEY UPDATE program_id=VALUES(a), program_code=VALUES(b), lender_id=VALUES(c), lender_code=VALUES(d), prog_lend=VALUES(e), rate=VALUES(f),
price=VALUES(g), date=VALUES(h), time=VALUES(i)”;
$result1 = mysql_query ($query2) or die (mysql_error());
header(“Location:admin_update_rate.php”);
?>