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@NogDogJan 23.2007 — #What does the HTML source code look like that it generates? I'm guessing that you'll need to grab the file name (perhaps with the basename() function) and append it to a full URL string or a document root path, e.g.:
Something small missing
I table that randomly selects an entry from a certain field my mySQL database
The field hold the directory for image uploads (C:/wamp/www/site/uploaded_files/1169563553.jpg)
So the page selects the fieldname contents and prints them out into the table cell
My question is, how can i get the image itself to be displayed ???
This is the code i am using to get the image directory from the database
[code=php] while ($list = mysql_fetch_array($result)) {
echo “{$list[‘file’]} “;
}
It is working as far as printing the directory into the cell but how do i get the image itself to show, where do i put the image tags on the ablove code or is that the correct way of doing this at all
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@NogDogJan 23.2007 — #What does the HTML source code look like that it generates? I'm guessing that you'll need to grab the file name (perhaps with the basename() function) and append it to a full URL string or a document root path, e.g.:[code=php]
echo "<img src='/site/uploaded_files/".basename($list['file'])."' alt=''>";
[/code]