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<?php include(‘menu.php’); ?>

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Jan 22.2007

When I clicked link, menu.php will be opened in div. Is it possible?

<a>Link</a>
<div></div>

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PHP

3 Comments(s) ↴

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@NightShift58Jan 22.2007 — No, because the include takes place before the click...
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@samanyoluauthorJan 22.2007 — I found this:



&lt;html&gt;
&lt;head&gt;
&lt;script type="text/javascript"&gt;
function showMenu(){
if(document.getElementById('menu').style.display=='block'){
document.getElementById('menu').style.display='none';
}else{
document.getElementById('menu').style.display='block';
}
}
&lt;/script&gt;
&lt;/head&gt;&lt;body&gt;
&lt;u onClick="showMenu()"&gt;open menu&lt;/u&gt;&lt;br&gt;
&lt;div id="menu" style="display: none"&gt;&lt;?php include("menu.php"); ?&gt;&lt;/div&gt;&lt;/body&gt;
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@NightShift58Jan 22.2007 — That should do it... The alternative would've been AJAX... So this is better...
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