handling onclick window.open

hi,

i have a mysql table called footers.it’s fields are as follows
id–caption–content
1–aboutus–some company info
2–privacy–privacy info
3–copyright–copyright info

here i retrieved all the captions from table and print in the footer position on my form as footer menu.what i want to do actually is when i click aboutus,it should open small window and display the aboutus content from mysql table,similarly when i click privacy,it should open a small window and should display privacy info like that.everything i did,but when i click aboutus,it shows all the three records from table.i want to display uniquely.means if i click aboutus it should display only aboutus info in small window like that..any of your help will be greatly appreciated

here is my code
<?php
$conn4=mysql_connect(“localhost”,””,””);
mysql_select_db(“jrm”,$conn4);
$sql=”SELECT * FROM footers”;
$result=mysql_query($sql,$conn4) or die (mysql_error());
echo “<center><table border=’0′ style=’text-align:left;’><tr>”;
while($newarray=mysql_fetch_array($result))
{
$caption=$newarray[‘caption’];

echo “<center><a style=’text-decoration:underline;’

href onclick=window.open(‘xyz.php’,”,’top=200,left=350,screenY=0,screenX=0,width=400,height=300,scrollbars=yes’);>
<td><font color=’white’><b>”.$caption. “&nbsp;&nbsp;</b></font></td></a></center>”;
}
echo “</tr></table></center>”;
?>

xyz.php
——

<?php

$conn4=mysql_connect(“localhost”,””,””);
mysql_select_db(“jrm”,$conn4);
$sql=”SELECT * FROM footers”;
$result=mysql_query($sql,$conn4) or die (mysql_error());
while($newarray=mysql_fetch_array($result))
{
$caption=$newarray[‘caption’];
$content=$newarray[‘content’];

echo “<center><b><u><font color=’navy’>”.$caption.”</font></b></u><br><font color=’green’>”.$content.”</font></center>”;
}

?>

is it possible without using xyz.php file,i will display the $content in small window directly

thanks
mrjameer

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