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loop problems

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Dec 19.2006

ok i want this statement that only display data if the search criteria match

[code=php]

}
$query = “SELECT * FROM `business_info` WHERE `make`=’make’ AND `type`=’type’ AND `Categories` LIKE ‘%”.$Categories.”%'”;
$result = mysql_query($query) or die (mysql_error());
$num_result = mysql_num_rows($result);
echo “<table>”;
if($num_result <= 0){
echo(“No Results found.”);
exit;
}

[/code]

this is my display

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PHP

5 Comments(s) ↴

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@bokehDec 19.2006 — So, what is your question/problem?
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@NightShift58Dec 19.2006 — I think your post got cutoff somewhere. Can you resubmit with the rest of the post?
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@franknuauthorDec 20.2006 — ok, i only posted the part that needs work

basicly what i need is this

if ( make==make and type==type)

SELECT * FROM business_info WHERE make='make' AND type='type' AND Categories LIKE

so they all have to match if i have a Caterories but it doesnt match with the make and type them it wont display anything
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@NightShift58Dec 20.2006 — I'm not getting the point.

Why do you want to apply an IF condition in the script and then again in the SQL query?
Copy linkTweet thisAlerts:
@bokehDec 20.2006 — [code=php]$query =
"SELECT * ".
"FROM business_info ".
"WHERE make='make' ".
"AND type='type'".
((!empty($Categories)) ? " AND Categories LIKE '%".$Categories."%'":'');[/code]
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