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save an array into a session

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Nov 06.2006

Here is what I currently have:

[code=php]$sql2 = mysql_query(“SELECT * FROM images WHERE user_id=’$_SESSION[id]'”)or die(mysql_error());
$row2 = mysql_fetch_array($sql2);
print_r(explode(“”, $row2[‘image_name’], -1));[/code]

I am searching the DB for the image names, and then putting them into an array. Once I get that done, I will switch out print_r with a variable, then I will save that variable into a session. But right now I am getting this error I don’t know what it means:

[B]Warning[/B]: explode() [function.explode]: Empty delimiter. in C:Program Files[B]xampphtdocsportfoliocheck_login.php[/B] on line [B]16[/B]

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PHP

2 Comments(s) ↴

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@The_Little_GuyauthorNov 06.2006 — Ok I removed the warning, but The array shows only one variable in it, and there should be 2.

[code=php]print_r(explode(' ', $row2['image_name']));[/code]
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@The_Little_GuyauthorNov 06.2006 — OK... I got it to get the values:

Here is how it looks:

[B]Array ( [0] => 123 [image_name] => 123 [1] => 2 [user_id] => 2 )

Array ( [0] => 12344 [image_name] => 12344 [1] => 2 [user_id] => 2 )[/B]

I need to get [image_name], and place it into an array

here is what I currently have:
[code=php]
while($row2 = mysql_fetch_array($sql2)){
#$img_array = implode(',', $row2['image_name']);
print_r($row2);
}
#$_SESSION['images'] = $img_array;

#print_r($img_array);
[/code]
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