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str_replace full words only

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Oct 25.2006

I have a word list I am using to remove common words from a user’s input. I’m using str_replace with an array of the words but this is causing some problems. Able is a word in the list so this removes able from any word, such as available. Is there a single line solution to this without doing an if… then?

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PHP

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@so_is_thisOct 25.2006 — Yes, just use the syntax to operate on a word boundary.

EDIT: I went and looked it up. It is the b selector.
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@ephmynusauthorOct 25.2006 — Thanks. Where is the list of all of these options?
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@so_is_thisOct 25.2006 — Various places -- but I find it easier to go here:

[URL=http://msdn.microsoft.com/library/en-us/script56/html/ab0766e1-7037-45ed-aa23-706f58358c0e.asp]MSDN Regular Expression Syntax[/URL]

I guess a PHP-specific reference would be better:

[url=http://us2.php.net/manual/en/reference.pcre.pattern.syntax.php]PHP Regular Expression Syntax[/url]
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@bokehOct 25.2006 — b is a zero width assertion that works as part of a regex. Str_replace is not a regex function. You could either switch to a regex function (preg_replace) or continue to use str_replace but put a space before and after the word in your search array and replace it with a space. Example: [code=php]$done = str_replace(' able ', ' ', $target);[/code]
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@so_is_thisOct 25.2006 — Whoops! I overlooked the fact that [B]str_replace()[/B] was involved here. Sorry.

Yes, to use b you would have to switch to the [B]preg_replace()[/B] function.
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