mysql_fetch_array(): supplied argument is not a valid MySQL result resource

I keep getting that error message. I’m trying to get data from my database into an array to display different columns on the page

[code=php]
<?php

$link=mysql_connect(“localhost”, “username”, “password”)
or die(‘I cannot connect to the database because: ‘ . mysql_error());
mysql_select_db (“database”, $link);
$sql=”SELECT Name, Creator, Category, Socks, Steps, Difficulty, ImageType, ID
FROM Models
WHERE ID = ‘$_GET[id]’ AND Confirmed = 1″;

$result=mysql_fetch_array(mysql_query($sql, $link) or die(mysql_error()));?>

<DIV CLASS=”content”>
<DIV ID=”leftcolumn”>
Creator: <?php echo $result[‘Creator’]; ?><BR>
Difficulty: <?php echo $result[‘Difficulty’]; ?><BR>
Socks: <?php echo $result[‘Socks’]; ?><BR>
<?php echo $result[‘Steps’]; ?></DIV>
<DIV ID=”rightcolumn”><IMG SRC=”http://models.sockigami.com/images/models/<?php echo $result[‘ID’]; ?>. <?php echo $result[‘ImageType’]; ?>” ALT=”<?php echo $result[‘Model’]; ?>”></DIV></DIV>

[/code]

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