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HELP!! Java is driving me nuts!!

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Sep 03.2006

I am new to Java and to be quite honest I am not liking it too much!

If I were asked to create a javascript function named jump_to_link(weblist) and within this function, create a variable named url_number that is equal to the selectedIndex property of the weblist variable; set the location object to the value of the selected option in the weblist field, if the selected option has the object name weblist.options[url_number]; and then to run the function whenever the user selects an item from one of the three selection lists in the form.

This is what I have so far:

function jump_to_link(weblist)
url_number=document.formName.selectBoxName[document.formName.selectBoxName.options.selectedIndex].value
=weblist.options[url_number}.value

Please help!!! Thanks! ?

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JavaScript

2 Comments(s) ↴

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@JMRKERSep 04.2006 — To begin with, you have a typo error.

[code=php]
 function jump_to_link(weblist)
url_number=document.formName.selectBoxName[document.formName.selectBoxName.options.selectedIndex].value
=weblist.options[url_number}.value
[/code]

should be '[url_number].value' instead
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@CrazyMerlinSep 04.2006 — to start with...

this is not Java....it is javascript...very different.

now look at your function.....toward the end.

you are trying to reference 'url_number' but until the line has been executed, url_number does not exist, as that is the line that creates it.

<i>
</i>document.formName.selectBoxName[document.formName.selectBoxName.options.selectedIndex].value


is wrong...

your selectbox should have an id attribute like:
<i>
</i>&lt;select id='select_1' ...


then you could say:
<i>
</i>var this_select = document.getElementById('select_1');
var url_number = this_select[this_select.selectedIndex].value;


what you do with the url_number after that I have no idea....you have a way to go, but keep going.
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