php refresh page

@kprocAug 27.2006

is there a php function that I can add to my code to refresh the page after it comes to the end of my script.

thank you

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15 Comments(s) _↴

@delr2691Aug 27.2006 — #no.. if you've already sent content, you can not "refresh" the page..

you can send some headers to change the location but just before sending any content..
[code=php]header("Location: http://your.domain.com/bla.php");[/code]

But you may wanna try JavaScript to do so..

@JickAug 27.2006 — #You could echo a refresh meta tag at the end of the script just before it exits. Like this:

[code=php]<?php
 # Your script here...
 # Your script here...
 # Your script here...
 
 echo('<meta http-equiv="refresh" content="20">');
 ?>[/code]

Could that work...? I'm not exactly sure if that will work but it was just an idea that popped into my head when I read your post. I'm sorry if it doesn't work. If it does, I hope that helps. ?

@kprocauthorAug 27.2006 — #no, does nothing, thank you for taking time to post

@NogDogAug 27.2006 — #First question: why do you need to refresh your page at the end of your script? (I can't think of a reason why you would, but that doesn't mean there isn't one.)

@kprocauthorAug 27.2006 — #I have a form that deletes data from a table. The user chooses the item from the active page and presses the button. The item is deleted but they have to click a link to refresh the page.

@NogDogAug 27.2006 — #Well, it seems if you did the form processing and database update and [i]then[/i] generated your page output, there would be no reason to refresh -- but maybe I'm missing something?

@kprocauthorAug 27.2006 — #attached the code to give an idea what is happening. I working with the delete section

I thought that when I get the end the delete it would reload the table but no such luck

[code=php]
 <?
 
 include 'db.php';
 
 $active_id = $_SESSION['user_id'];
 
 $buddy_id = $_POST['addbuddy'];
 
 $array = explode(",",$buddy_id);
 
 $post_b_id = $array[0];
 $first_name = $array[1];
 $last_name = $array[2];
 
 
 $query = mysql_query("SELECT * FROM buddylink WHERE owner_id ='$active_id'") or die ("Search Error" .mysql_error());
 
  $tbl .= "<form name='dBuddy' method='post' action='addbuddy.php'>";
  $tbl .='<table width="200" border="1" cellspacing="2">';
  $tbl .='<tr>';
  $tbl .='<td>Delete</td>';
  $tbl .='<td width="303">Name:</td></tr>';
 
 while($r=mysql_fetch_assoc($query)) {
 
 $f_name = $r['first_name'];
 $l_name = $r['last_name'];
 $b_id = $r['buddy_id'];
 
 
 $tbl .= "<tr><td align=center><input type=radio name='deletebuddy' value='$b_id'></td>";
 $tbl .="<td><a href='SearchDetails.php?owner_id=$b_id'>$f_name $l_name</a></td></tr>";
 
 }
 
 $tbl .="</table>"; 
 $tbl .= "<input align=left type='submit' name='submit' value='Delete>";
 $tbl .= "</form>";
 
 if($buddy_id != ""){
 
 // ADD TO TABLE
 $sql = mysql_query("INSERT INTO buddylink (owner_id, buddy_id, first_name, last_name, added)VALUES('$active_id', '$post_b_id', '$first_name', '$last_name', now())")or die ("Link Create Error:" .mysql_error());
 
 
 
 }
 
 $d_buddy = $_POST['deletebuddy'];
 
 if($d_buddy != ""){
 
 mysql_query("DELETE FROM buddylink WHERE buddy_id = '$d_buddy'");
 
 echo 'Buddy has been deleted';
 
 
 
 }
 echo $tbl;
 
 ?>
 [/code]

@delr2691Aug 27.2006 — #you are creating the whole html output before deleting the entry.. the page wont show the updates not even when you add.. you can try this instead:

[code=php]
 <?
 
 include 'db.php';
 
 $active_id = $_SESSION['user_id'];
 
 $buddy_id = $_POST['addbuddy'];
 
 $array = explode(",",$buddy_id);
 
 $post_b_id = $array[0];
 $first_name = $array[1];
 $last_name = $array[2];
 
 
 
 
 
 if($buddy_id != ""){
 
 // ADD TO TABLE
 $sql = mysql_query("INSERT INTO buddylink (owner_id, buddy_id, first_name, last_name, added)VALUES('$active_id', '$post_b_id', '$first_name', '$last_name', now())")or die ("Link Create Error:" .mysql_error());
 
 
 
 }
 
 $d_buddy = $_POST['deletebuddy'];
 
 if($d_buddy != ""){
 
 mysql_query("DELETE FROM buddylink WHERE buddy_id = '$d_buddy'");
 
 echo 'Buddy has been deleted';
 
 
 
 }
 
 
 
 
 $query = mysql_query("SELECT * FROM buddylink WHERE owner_id ='$active_id'") or die ("Search Error" .mysql_error());
 
  $tbl .= "<form name='dBuddy' method='post' action='addbuddy.php'>";
  $tbl .='<table width="200" border="1" cellspacing="2">';
   $tbl .='<tr>';
  $tbl .='<td>Delete</td>';
  $tbl .='<td width="303">Name:</td></tr>';
 
 while($r=mysql_fetch_assoc($query)) {
 
 $f_name = $r['first_name'];
 $l_name = $r['last_name'];
 $b_id = $r['buddy_id'];
 
 
 $tbl .= "<tr><td align=center><input type=radio name='deletebuddy' value='$b_id'></td>";
 $tbl .="<td><a href='SearchDetails.php?owner_id=$b_id'>$f_name $l_name</a></td></tr>";
 
 }
 
 $tbl .="</table>";
 $tbl .= "<input align=left type='submit' name='submit' value='Delete>";
 $tbl .= "</form>";
 
 echo $tbl;
 
 ?>
 [/code]

Hope that works.. ?

@kprocauthorAug 27.2006 — #thank you for the reply are fixing up my code. I figured I was doing somthing wrong

I have been testing if user has posted by ($variable != ""){

code .............

}

Is this a good way to do this or is there a better way.

@delr2691Aug 27.2006 — #Your welcome ?

And I guess you should do it this way.. [well, actually is the way I'm used to ?]

[code=php]
 if (isset($_POST['input']) && !empty($_POST['input'])) {
 //add, delete or anything here..
 } else {
 //just output the table
 }
 [/code]

@NogDogAug 27.2006 — #Just be aware that when you do a "==" or "!=" comparison or when using the empty() function; the values 0 (zero), "" (empty string) and the boolean FALSE constant are all treated as equivalent. Therefore, if zero or a boolean false is a valid entry, then you should use "===" or "!==" against an empty string when doing your comparison. Plus, I normally trim() the inputs first to get rid of leading/trailing spaces:

[code=php]
 foreach($_POST as $key => $val)
 {
 $_POST[$key] = trim($val);
 }
 if(isset($_POST['input']) and $_POST['input'] !== '')
 {
 // good to go
 }
 else
 {
 // missing a required entry
 }
 [/code]

@arcticwarrioJul 05.2012 — #[code=php]header('Location: '.$_SERVER['PHP_SELF']);[/code]

@snipe42Jul 05.2012 — #[code=php]header('Location: '.$_SERVER['PHP_SELF']);[/code][/QUOTE]

i use this,but inside a form.
[code=php]<form name='myform' method='post' action='".$_SERVER['PHP_SELF']."?action=del'>[/code]

but script for getting del action is above it.

[code=php]if ($_GET['action'] == "del")
 {
 // get the hidden value
 $n = $_POST['n'];
 
 for ($i=0; $i<=$n-1; $i++)
 {
 if (isset($_POST['NPM'.$i]))
 {
 $NPM = $_POST['NPM'.$i];
 $query = "DELETE FROM mahasiswa WHERE NPM = '$NPM'";
 mysql_query($query);
 }
 }
 }
 [/code]

it's didnt show you any message, but its actually refresh the page.

@AdelineZNov 21.2012 — #Hi there!

I have a similar problem.

I want to delete from a table of mysql database. My problem is that after i delete a second record, only if i press 'Ctrl+F5' that record disapear.Meanwhile, from the database that record is deleted. What should i do? I have to complete that i'm working on apache server, on localhost, there was no problem.

Thanks !

This is the code:

[code=php]<?php
 ob_start();
 
   include "conectarebd.php";
   $idul=$_GET['id'];
   mysql_query("DELETE FROM angajator WHERE id='$idul' ") or die(mysql_error());
 
   header('location: http://domain.ro/edit_angajator_button.php'.$random);
 
 ?>[/code]

@AdelineZNov 22.2012 — #I forgot to remove '$random' from my code; that was another way that i tried to make it work, but it failed too.

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