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@NogDogAug 24.2006 — #Probably due to not closing all of your if and/or while blocks. Try indenting your code to make it visually easier to see where such blocks begin and end. For instance, this section near the beginning looks suspicious (I added the indenting and deleted some unnecessary "?><?php" lines for clarity):
The first 3 if blocks seem to do the same thing, and you don't close them so each is being nested inside of the prior if -- is this really what you intended?
Parse error: parse error, unexpected $end
Hi All
Wondering if you could help me…
I get the following error when using [url]http://www.rhwebdesign.net/portfolio.phps
[QUOTE]
Parse error: parse error, unexpected $end in pathidonotwanttoreleaseonforums on line 339
Because I am on the line of insanity, can someone please point me in the right direction of the code thats dodgy, or better still, give me some corrected code?
I would love you forever if you did ? hehe
Thanks
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@NogDogAug 24.2006 — #Probably due to not closing all of your if and/or while blocks. Try indenting your code to make it visually easier to see where such blocks begin and end. For instance, this section near the beginning looks suspicious (I added the indenting and deleted some unnecessary "?><?php" lines for clarity):[code=php]
<?php
if(!isset($_POST['Submit'])){
$id = $_GET['edit'];
$sql = "SELECT * FROM portfolio WHERE id='$id'";
$result = mysql_query($sql) or die ("<b>ERROR: </b>" . mysql_error() . "<b>SQL: </b>$sql");
$rows = mysql_num_rows($result);
while ($portfolio = mysql_fetch_array($result)) {
$portfolio_title = $portfolio["title"];
$portfolio_client = $portfolio["client"];
$portfolio_type = $portfolio["type"];
$portfolio_project = $portfolio["project"];
$portfolio_description = $portfolio["description"];
$portfolio_picturename = $portfolio["picturename"];
$portfolio_alt = $portfolio["alt"];
$portfolio_url = $portfolio["url"];
}
if(!isset($_POST['Submit'])){
$id = $_GET['edit'];
$sql = "SELECT * FROM portfolio WHERE id='$id'";
$result = mysql_query($sql) or die ("<b>ERROR: </b>" . mysql_error() . "<b>SQL: </b>$sql");
$rows = mysql_num_rows($result);
while ($portfolio = mysql_fetch_array($result)) {
$portfolio_title = $portfolio["title"];
$portfolio_client = $portfolio["client"];
$portfolio_type = $portfolio["type"];
$portfolio_project = $portfolio["project"];
$portfolio_description = $portfolio["description"];
$portfolio_picturename = $portfolio["picturename"];
$portfolio_alt = $portfolio["alt"];
$portfolio_url = $portfolio["url"];
}
if(!isset($_POST['Submit'])){
$id = $_GET['edit'];
$sql = "SELECT * FROM portfolio WHERE id='$id'";
$result = mysql_query($sql) or die ("<b>ERROR: </b>" . mysql_error() . "<b>SQL: </b>$sql");
$rows = mysql_num_rows($result);
while ($portfolio = mysql_fetch_array($result)) {
$portfolio_title = $portfolio["title"];
$portfolio_client = $portfolio["client"];
$portfolio_type = $portfolio["type"];
$portfolio_project = $portfolio["project"];
$portfolio_description = $portfolio["description"];
$portfolio_picturename = $portfolio["picturename"];
$portfolio_alt = $portfolio["alt"];
$portfolio_url = $portfolio["url"];
}
if(!isset($_POST['Submit'])){
$id = $_GET['edit'];
$pg4 = "SELECT * FROM page4 WHERE id='$id'";
$result = mysql_query($pg4) or die ("<b>ERROR: </b>" . mysql_error() . "<b>pg4: </b>$pg4");
$rows = mysql_num_rows($result);
while ($page4 = mysql_fetch_array($result)) {
$page4_title = $page4["title"];
$page4_client = $page4["client"];
$page4_type = $page4["type"];
$page4_project = $page4["project"];
$page4_description = $page4["description"];
$page4_picturename = $page4["picturename"];
$page4_alt = $page4["alt"];
$page4_url = $page4["url"];
}
?>
[/code]The first 3 if blocks seem to do the same thing, and you don't close them so each is being nested inside of the prior if -- is this really what you intended?