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Syntax error ???

Parse error: parse error in H:xampphtdocswwwknowledgewl-kbf22adminaccount_details.php on line 3

Heres the code:

[code=php]
line 3: <?PHP if ($val != final()){ ?>
<font size=”3″><b><font size=”3″><b><font size=”2″ face=”Arial, Helvetica, sans-serif”><b><font size=”2″ face=”Arial, Helvetica, sans-serif”><b><font size=”2″ face=”Arial, Helvetica, sans-serif”><font size=”4″ face=”Arial, Helvetica, sans-serif” color=”#336699″>
<?PHP
$result = mysql_query (“SELECT * FROM faqAdmin
WHERE user LIKE ‘$usernow’

limit 1
“);
$row = mysql_fetch_array($result)
?>
</font></font></b></font></b></font></b></font></b></font></strong></font></p>
<form name=”form1″ method=”post” action=””>
<table width=”450″ border=”0″ cellspacing=”0″ cellpadding=”5″>
<tr>
<td width=”100″ bgcolor=”#F3F3F3″><div align=”left”><font size=”2″ face=”Arial, Helvetica, sans-serif”>Username</font></div></td>
<td width=”350″ bgcolor=”#F3F3F3″><font size=”2″ face=”Arial, Helvetica, sans-serif”>
<?PHP print $row[“user”]; ?></font></td>
</tr>
<tr>
<td width=”100″><div align=”left”><font size=”2″ face=”Arial, Helvetica, sans-serif”>Password</font></div></td>
<td width=”350″><font size=”2″ face=”Arial, Helvetica, sans-serif”>
<input name=”pass” type=”password” id=”pass” value=”<?PHP $passnow=base64_decode ($row[“pass”]); print $passnow; ?>”>
</font></td>
</tr>
<tr>
<td width=”100″ bgcolor=”#F3F3F3″><div align=”left”><font size=”2″ face=”Arial, Helvetica, sans-serif”>Name</font></div></td>
<td width=”350″ bgcolor=”#F3F3F3″><font size=”2″ face=”Arial, Helvetica, sans-serif”>
<input name=”name” type=”text” id=”name” value=”<?PHP print $row[“name”]; ?>”>
</font></td>
</tr>
<tr>
<td width=”100″><div align=”left”><font size=”2″ face=”Arial, Helvetica, sans-serif”>E-mail</font></div></td>
<td width=”350″><font size=”2″ face=”Arial, Helvetica, sans-serif”>
<input name=”email” type=”text” id=”email” value=”<?PHP print $row[“email”]; ?>”>
</font></td>
</tr>
<tr>
<td width=”100″><font size=”2″ face=”Arial, Helvetica, sans-serif”>&nbsp;</font></td>
<td width=”350″><p><font size=”2″><font face=”Arial, Helvetica, sans-serif”>
<br>
<input type=”submit” name=”Submit” value=”Submit”>
<input name=”val” type=”hidden” id=”val” value=”final”>
</font><font size=”2″><font face=”Arial, Helvetica, sans-serif”> </font><font size=”2″><font size=”2″><font face=”Arial, Helvetica, sans-serif”>
<input name=”nl” type=”hidden” id=”nl” value=”<?PHP print $nl; ?>”>
</font></font></font></font><font face=”Arial, Helvetica, sans-serif”>
</font></font></p></td>
</tr>
</table>
</form>
<?PHP
}
else {
?>
<p><font size=”2″ face=”Arial, Helvetica, sans-serif” color=”#990000″>Your account
settings have been updated.</font> <font size=”2″ face=”Arial, Helvetica, sans-serif” color=”#FF0000″>
<?PHP
$pass=base64_encode($pass);
mysql_query(“UPDATE faqAdmin SET pass=’$pass’,name=’$name’,email=’$email’ WHERE (user=’$usernow’)”);
?>
<br>
</font> </p>
<p> <font size=”2″ face=”Arial, Helvetica, sans-serif” color=”#FF0000″> </font>
<?PHP } ?>
[/code]

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PHP

4 Comments(s)

Copy linkTweet thisAlerts:
@balloonbuffoonMar 28.2006 — A lot of times the syntax error occurs on the line previous to the one it says its on, so what are the first two lines?
Copy linkTweet thisAlerts:
@solidaritiauthorMar 29.2006 — These are the first lines:

[code=php]
<p><font color="#336699" size="4" face="Arial, Helvetica, sans-serif"><strong>Account
Details
[/code]
Copy linkTweet thisAlerts:
@NogDogMar 29.2006 — Where does $val get set?

Where does function final() get defined?
Copy linkTweet thisAlerts:
@gameguy43Mar 30.2006 — my best guess is that final() isnt returning the right kind of value. check types on it and what its being checked as !=
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