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If isset & equal OR not at all.

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Dec 06.2020

Crazy title. But I’m looking through some results.

If a GET is set (isset) I want to filter to results only of that ID otherwise show all.

` if (isset($_GET[‘ID’]) && $Person->getFunctionID() == $_GET[‘ID’]){`

I’m I’m looping through a student list. If the ID is set as a GET then check if the property is set to the same ID.

IF no ID is set via GET then show them all.

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PHP

3 Comments(s) ↴

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@NachfolgerDec 06.2020 — @kiwis80#1625646

Assuming you're looping through an array,

``PHP<i>
</i>$functionID = (isset($_GET['ID']) &amp;&amp; !empty($_GET['ID']) &amp;&amp; is_numeric($_GET['ID']) ? $_GET['ID'] : 0);

foreach ($Persons as $Person) {
if ($functionID != 0 &amp;&amp; $Person-&gt;getFunctionID() == $functionID) {
echo "ID was set, and matches Person function ID";
} else if ($functionID == 0) {
echo "functionID was not set";
}
}<i>
</i>``

Might be subject to revisions, just a generic example.
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@wdmangaloreDec 06.2020 — Good one
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@NogDogDec 06.2020 — Couldn't think of a really concise way to do it, and gave up after coming up with this, FWIW:
<i>
</i>$personID = $Person-&gt;getFunctionID();
if(!isset($_GET['ID'])) {
do_thing($theData);
}
elseif($_GET['ID'] == $personID) {
do_thing($theData, $personID));
}

function do_thing($data, $id=null) {
foreach($data as $row) {
if(empty($id) or $id == $row['some_id']) {
// do thing with this row
}
}
}
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